Answer this question and break it down using the following(Huge equation, show work if needed) this process involves breaking down the expression and answering the given.

Given:
[tex]y=x^2-3x-4[/tex]1) Function notation
[tex]f(x)=x^2-3x-4.[/tex]2) put x=-2
[tex]\begin{gathered} f(-2)=(-2)^3-3(-2)-4 \\ f(-2)=2^2+3\cdot\: 2-4 \\ f(-2)=4+6-4 \\ f(-2)=6 \end{gathered}[/tex]3) Put x=-1
[tex]\begin{gathered} f(-1)=(-1)^3-3(-1)-4 \\ f(-1)=1+3-4 \\ f(-1)=0 \end{gathered}[/tex]4) f(x)=-4 to find x.
when x =0 f(x)=-4
when x=3 f(x)=-4