Find the area of the shaded region under the standard normal distribution to the left of the given z-score.Round your answer to four decimal places.-3-2-103412z = 1.56ZQP(Z < 1.56)=

ANSWER:
0.9406
STEP-BY-STEP EXPLANATION:
Given:
z = 1.56
Therefore we must calculate the following according to the graph:
[tex]P\left(z<1.56\right)[/tex]We calculate it by means of the table, just like this:
P(z < 1.56) = 0.9406