Given,
The mass of the box, m=16.6 kg
The force exerted by Roy, F=99.1 N
The coefficient of friction between the floor and the box, μ=0.324
The distance for which Roy pushes the box, d=11.4 m
The work done is given by the product of the force exerted by a source and the distance for which the force was exerted.
Thus the work done by Roy is given by,
[tex]W=F\times d[/tex]On substituting the known values,
[tex]\begin{gathered} W=99.1\times11.4 \\ =1129.74\text{ J} \\ \approx1130\text{ J} \end{gathered}[/tex]Thus the work done by Roy is 1130 J
