The equation of a circle, given center (h, k) with radius r is given by the formula
[tex](x-h)^2+(y-k)^2=r^2[/tex]Comparing, this equation with the given equation
[tex](x+4)^2+(y-1)^2=16[/tex]we have the foolowing:
x-h = x + 4
subtract x from both sides
-h = 4
h= -4
y-k = y-1
subtract y from both sides
-k = -1
k = 1
[tex]\begin{gathered} r^2=16 \\ r=\sqrt[]{16} \\ r=4 \end{gathered}[/tex]The center of the circle is ( -4, 1) while the radius is 4 units
