Respuesta :

Data and background

• The length (l) of a rectangle is 5 yd longer than its width (w).

,

• The perimeter (P) of the rectangle is 70 yd.

,

• The perimeter (P) of a rectangle is given by:

[tex]P=2w+2l[/tex]

where w represents the width and l the length.

Procedure

We have to build two equations with the information given.

• Equation 1

[tex]70=2w+2l[/tex]

• Equation 2

[tex]l=w+5[/tex]

Then, we have to replace the isolated expression of l from equation 2 in equation 1:

[tex]70=2w+2(w+5)[/tex]

Simplifying the parenthesis:

[tex]70=2w+2w+10[/tex]

Adding similar terms:

[tex]2w+2w=70-10[/tex][tex]4w=60[/tex][tex]w=\frac{80}{4}[/tex][tex]w=15[/tex]

Now that we know the value of w, we can calculate the value of l with equation 2:

[tex]l=15+5[/tex][tex]l=20[/tex]

Answer:

• Width: 15yd

,

• Length: 20yd