Solution
For this case we have the following:
[tex](\frac{25}{4})^{-3x}=\frac{3125}{32}[/tex]We can apply natural log in both sides and we have:
[tex]-3x\ln (\frac{25}{4})=\ln (\frac{3125}{32})[/tex]And then we can solve for x like this:
[tex]x=-\frac{1}{3}\cdot\frac{\ln (\frac{3125}{32})}{\ln (\frac{25}{4})}=-\frac{5}{6}[/tex]Then the solution for this case is :
x= -5/6
