Given data
*The given speed of the penguin is v = 1.6 m/s
*The given time is t = 3.0 s
*The value of the acceleration due to gravity is g = 9.8 m/s^2
The formula for the height of the vertical face of the glacier is given as
[tex]h=\frac{1}{2}gt^2[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} h=\frac{1}{2}(9.8)(3.0)^2 \\ =44.1\text{ m} \end{gathered}[/tex]Hence, the vertical face of the glacier is h = 44.1 m
The formula for the distance of the penguin from the base to hit the water is given as
[tex]d=vt[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} d=(1.6)(3.0) \\ =4.8\text{ m} \end{gathered}[/tex]Hence, the distance of the penguin from the base to hit the water is d = 4.8 m