Given:
[tex]x^2+3x=4[/tex]Required:
We need to find root by Completing the Square method.
Explanation:
[tex]\begin{gathered} x^{2}+3x=4 \\ x^2+3x-4= \\ x^2+2*\frac{3}{2}x-4=0 \\ \\ x^2+2*\frac{3}{2}x-(\frac{3}{2})^2+(\frac{3}{2})^2-4=0 \\ \\ (x+\frac{3}{2})^2=\frac{25}{4} \\ \\ x+\frac{3}{2}=\pm\frac{5}{2} \end{gathered}[/tex]now find the values of x
[tex]\begin{gathered} x=\frac{5}{2}-\frac{3}{2}=1 \\ \\ or \\ x=-\frac{5}{2}-\frac{3}{2}=-4 \end{gathered}[/tex]Final answer:
Solutions of given equation are x=1 and x=-4
