Answer:
x = 8 or x = 2
Explanation:
Given the below quadratic equation;
[tex]x^2-10x+16=0[/tex]To solve the above using the completing the squares method, we'll have to follow the below-outlined steps;
1. Subtract 16 from both sides of the equation;
[tex]\begin{gathered} x^2-10x+16-16=0-16 \\ x^2-10x=-16 \end{gathered}[/tex]2. Add 1/2 of the coefficient of x squared to both sides of the equation;
[tex]\begin{gathered} x^2-10x+(\frac{-10}{2})^2=-16+(\frac{-10}{2})^2 \\ x^2-10x+25=-16+25 \\ x^2-10x+25=9 \end{gathered}[/tex]3. Factor the left-hand side of the equation into a perfect square;
[tex](x-5)^2=9[/tex]4. Let's go ahead and take the square root of both sides and solve for x;
[tex]\begin{gathered} x-5=\sqrt[]{9} \\ x-5=3 \\ x=8 \\ Or \\ x-5=-3 \\ x=5-3 \\ x=2 \end{gathered}[/tex]