Given:
[tex]8\mleft(x-2\mright)+9<3\mleft(x-1\mright)+5x[/tex]To solve:
[tex]\begin{gathered} 8\mleft(x-2\mright)+9<3\mleft(x-1\mright)+5x \\ 8x-16+9<3x-3+5x \\ 8x-7<8x-3 \\ 8x-8x<7-3 \\ 0<4 \end{gathered}[/tex]Since, the relation is true. That is, 0 is less than 4.
Hence, the answer is, all the real numbers.
