Respuesta :
the tocal cost of the electric bill from Sep1 to Oct is $8167.5
Explanation
Step 1
find the consumption of the month by obtaining the difference of the registered data
from Sept 1 to Oct 1
[tex]\begin{gathered} 13,814kw-hr-12,725kw-hr=\text{comsuption}(C) \\ 1,089\text{ }kw-hr=C \end{gathered}[/tex]Step 2
now to know the total cost of the electric bill for that month, we need to use the expression
[tex]\text{total cost= unit cost}\cdot\text{ number of(kw-hr)}[/tex]then, let
[tex]\begin{gathered} \text{unit cost = 7 }\frac{1}{2}=7.5=7.5\frac{\text{ \$}}{kw-h} \\ total\text{ (kw-hr)=1,089 (kw-h)} \\ \end{gathered}[/tex]replace
[tex]\begin{gathered} \text{total cost= unit cost}\cdot\text{ number of(kw-hr)} \\ total\cos t=7.5\frac{\text{ \$}}{\text{kwh}}\cdot1.089)\text{kwh)} \\ total\cos t=8167.5 \end{gathered}[/tex]therefore, the tocal cost of the electric bill from Sep1 to Oct is $8167.5
Step 3
Now, do the same for the other monts
[tex]\begin{gathered} \text{June} \\ \text{total cost= unit cost}\cdot\text{ number of(kw-hr)}=7.5\frac{\text{ \$}}{\text{kwh}}\cdot\text{difference} \\ \text{total cost= unit cost}\cdot\text{ number of(kw-hr)}=7.5\frac{\text{ \$}}{\text{kwh}}\cdot(23006-21416) \\ \text{total cost= unit cost}\cdot\text{ number of(kw-hr)}=7.5\frac{\text{ \$}}{\text{kwh}}\cdot(159) \\ \text{total cost= unit cost}\cdot\text{ number of(kw-hr)}=11925 \end{gathered}[/tex]June Electric bill: $11925
[tex]\begin{gathered} \text{November} \\ \text{total cost= unit cost}\cdot\text{ number of(kw-hr)}=7.5\frac{\text{ \$}}{\text{kwh}}\cdot\text{difference} \\ \text{total cost= unit cost}\cdot\text{ number of(kw-hr)}=7.5\frac{\text{ \$}}{\text{kwh}}\cdot(9255-8316) \\ \text{total cost= unit cost}\cdot\text{ number of(kw-hr)}=7.5\frac{\text{ \$}}{\text{kwh}}\cdot9255-8316) \\ \text{total cost= unit cost}\cdot\text{ number of(kw-hr)}=7042.5 \end{gathered}[/tex]November electric bill: $7042.5
I hope this helps you
