Respuesta :

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[tex]\begin{gathered} \frac{1}{4}(12\text{ + x) + }\frac{1}{2}(x\text{ - 6)} \\ \frac{12}{4\text{ }}\text{ + }\frac{x}{4}\text{ + }\frac{x}{2}\text{ - }\frac{6}{4} \\ \frac{12}{4}\text{ - }\frac{6}{4}\text{ + }\frac{x}{4}\text{ + }\frac{x}{2} \\ \frac{6}{4}\text{ + }\frac{x\text{ + 2x}}{4} \\ \frac{3}{2}\text{ + }\frac{3x}{4} \end{gathered}[/tex]

The last line is the result