We have the following equation
[tex]\frac{1}{4}\cdot(28d+20)=d+11[/tex]Steps
1. Expand
[tex]\begin{gathered} \frac{1}{4}\cdot28d+\frac{1}{4}\cdot20=d+11 \\ 7d+5=d+11 \end{gathered}[/tex]2. substract 5 from both sides
[tex]7d+5-5=d+11-5[/tex]3. simplify
[tex]7d=d+6[/tex]4. substract d from both sides
[tex]7d-d=d+6-d[/tex]5. simplify
[tex]6d=6[/tex]6. divide by 6 and simplify
[tex]\begin{gathered} \frac{6d}{6}=\frac{6}{6} \\ d=1 \end{gathered}[/tex]Thus, we can see that d = 1
