In this case the answer is very simple.
To find the solution to the exercise we'll have to carry out several steps.
Step 01:
Data:
side = 12 in
hypotenuse = 13 in
Step 02:
Pythagoras Theorem
h² = a² + b²
13² = 12² + b²
[tex]\begin{gathered} b\text{ = }\sqrt[]{13^{2}\text{ -12² }} \\ b\text{ = }\sqrt[]{169-144}\text{ = }\sqrt[]{25} \\ b\text{ = 5 in} \end{gathered}[/tex]
Step 03:
Area
A = (b * h) / 2
[tex]A\text{ = }\frac{5\cdot12}{2}=\text{ }\frac{60}{2}=30in^2[/tex]
Step 04:
Perimeter
P = a + b + h
P = 12 + 5 + 13 = 30 in
The solution is:
Area A = 30 in²
Perimeter P = 30 in
