Given : Triangle JKL is similar to Triangle PQR.
So, the angle Q is corresponding to the angle K
From the triangle JKL :
[tex]\begin{gathered} \cos K=\frac{adjacent}{hypotenuse} \\ \\ \cos K=\frac{5}{13} \\ \\ \cos Q=\cos K=\frac{5}{13} \end{gathered}[/tex]
so, the answer is : the ratio = 5/13
