hello,
to find the axis of simmetry, we can use the formula below:
[tex]x\text{ = }\frac{-b}{2a}[/tex]Remembering: in a equation of 2nd degree, we have something like this:
[tex]ax^2+bx+c[/tex]So,
a = -2
b = -12
c = +36
Using the formula:
[tex]\begin{gathered} x\text{ = }\frac{-b}{2a} \\ x\text{ = }\frac{-(-12)}{2\cdot(-2)} \\ x=\frac{12}{-4} \\ x\text{ = -3} \end{gathered}[/tex]So, the axes of simmetry pass through X when its equal to -3.
