Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 73.4 Mbps. The complete list of 50 data speeds has a mean of x=16.23 Mbps and a standard deviation of s=18.01 Mbps.

Part A
The difference is given by
73.4-16.23=57.17 Mbps
Part B
we know that
s=18.01 Mbps
Divide 57.17 Mbps by 18.01 Mbps
so
57.17/18.01=3.17 standard deviations
Part C
The answer must be equal to the number of standard deviations (Part B)
z=3.17
Part D
Remember that
For X=57.17 Mbps -----------> z=3.17
so
For Z between -2 and 2
the answer is significantly low