[tex]\begin{gathered} \tan x=\frac{opposite}{adjacent} \\ \tan x=\frac{80}{16} \\ \tan x=5 \\ x=\tan ^{-1}(5) \\ x=79^o \end{gathered}[/tex]
SImilarly, another flag is raised at that same position sharing the same angle of depression as the formal flag
[tex]\begin{gathered} \tan 79=\frac{h}{18} \\ h=18\tan 79 \\ h=92.6ft \end{gathered}[/tex]
The height of the other flag is 92.6ft
