A fair coin is tossed 3 times in succession. The set of equally likely outcomes is {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT). Find the probability of getting a tail on the second toss.The probability of getting a tail on the second toss is __.
There is a total of 8 possible outcomes. In 4 of then, we have a tail on the second toss. Therefore, the probability of getting a tail on the second toss is 4/8 = 1/2 (or 0.5).
