A planet is moving at constant speed in a circular orbit around a star. In one complete orbit, what is the net amount of work done on the planet by the starâ€™s gravitational force: positive, negative, or zero? What if the planetâ€™s orbit is an ellipse, so that the speed is not constant? Explain your answers.

Question

contestada

Respuesta :

rafikiedu08 rafikiedu08 · Answer 1 · 2022-10-28T04:49:35+02:00

Work done by star's gravitational force is zero moving at constant speed in a circular orbit around a star

We know that,

Gravitational force is conservative force hence, work done by the gravitational force does not depends on path.

hence,

[tex]W=\int \vec(F)*d \vec(r)[/tex]

For the given case,

Planet started from one point and coming back at same point (one complete circle around the star).

hence,

[tex]W=\int _c \vec(F)*d \vec(r)=0[/tex]

Work done by star's gravitational force is zero.

Any item with mass is attracted to one another by the gravitational pull.Every item attracts every other body with a force that is directly proportional to the product of their masses and inversely proportional to the square of their separation, according to Newton's equations of gravitation.

To know more about gravitational force visit : https://brainly.com/question/24783651

#SPJ4