Given:
Height of the isosceles triangle = 4 inches
Base of triangle = 6 inches
Let's find the length of the legs of the traingle.
Let's sketch a figure which represents this isosceles triangle.
Since the triangle is an isoceles triangle, the length of the legs will be equal.
a = b
To find the length of the legs, apply Pythagorean Theorem:
[tex]c^2=a^2+b^2[/tex]Where:
a = 4 in
b = 3 in
Thus, we have:
[tex]\begin{gathered} c^2=4^2+3^2 \\ \\ c^2=16+9 \\ \\ c^2=25 \end{gathered}[/tex]Take the square root of both sides:
[tex]\begin{gathered} \sqrt[]{c}^2=\sqrt[]{25}^2 \\ \\ c=5 \end{gathered}[/tex]Therefore, the length of the legs of the isosceles triangle is 5 inches.
