We need to find x in term of j(x).
First, if we move -3 to the left hand side as +3, we have
[tex]j(x)+3=4x[/tex]By symmetry, we can write this result as
[tex]4x=j(x)+3[/tex]Now, we need to move the coefficient of x to the right hand side. This is given by
[tex]x=\frac{j(x)+3}{4}[/tex]which can be rewritten as
[tex]x=\frac{j(x)}{4}+\frac{3}{4}[/tex]which is the answer.
