By the thales theorem
[tex]\frac{x+2}{6}=\frac{6}{x-3}[/tex]
then
[tex](x-3)(x+2)=36[/tex][tex]x^2+2x-3x-6=36[/tex][tex]x^2-x-42=0[/tex]
solving the quadratic equation
then x will be equal to 7 or -6, but since x is a positive measure we conclude that x=7. Then we replace x for 7 in x+2 obtaining that BS=9
