right-handThe triangles are similar if, the ratios of their sides are equal
[tex]\frac{AE}{AC}=\frac{AW}{AL}[/tex]
[tex]\frac{8+8}{6+6}=\frac{8}{6}[/tex]
On the left-hand side
[tex]\frac{16}{12}=\frac{4}{3}[/tex]
and in the right-hand side, we have
[tex]\frac{8}{6}=\frac{4}{3}[/tex]
The left-hand side equals the right-hand side; therefore, the triangles are similar.
