If 6.95 mol of ethane (C2H6) undergo combustion according to the unbalanced equation C2H6 + O2 ——- CO2 + H2OHow many moles of O2 is required? Answer in units of mol.

If 695 mol of ethane C2H6 undergo combustion according to the unbalanced equation C2H6 O2 CO2 H2OHow many moles of O2 is required Answer in units of mol class=

Respuesta :

Answer

24.325 mol

Explanation

The unbalanced equation is:

C₂H₆ + O₂ → CO₂ + H₂O

The balanced equation will be:

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

Given mole of ethane = 6.95 mol

From the balanced equation:

2 mol of C₂H₆ is required by 7 mol of O₂

Therefore, 6.95 mol of C₂H₆wills requir:

[tex]\frac{6.95\text{ mol }C_2H_6\times7\text{ mol }O_{2}}{2\text{ mol }C_2H_6}=24.325\text{ mol of }O_{2}[/tex]

Hence, 24.325 mol of O2 is required.