SOLUTION:
To see if the lines are perpendicular, we find the slopes of both lines;
Line one (6,-4) and (0,1)
Line two (0,-2) and (5,4)
[tex]\begin{gathered} m_1=\frac{1-(-4)}{0-6}=-\frac{5}{6} \\ m_2=\frac{4-(-2)}{5-0}=\frac{6}{5} \end{gathered}[/tex]Since ;
[tex]m_1\times m_2=-\frac{5}{6}\times\frac{6}{5}=-1[/tex]The lines are perpendicular
