The diagonal of a square is 25ft. Find the length of ONE side of the square
we have that
Applying the Pythagorean Theorem
Let
c ----> the diagonal of the square
a----> the length of one side
so
c^2=a^2+a^2
c^2=2a^2
substitute the given values
25^2=2a^2
625=2a^2
a^2=312.5
a=17.68 units
or
exact value is
[tex]\begin{gathered} a=\sqrt[\square]{\frac{625}{2}} \\ a=\frac{25}{\sqrt[]{2}} \\ a=\frac{25\sqrt[]{2}}{2}\text{ ft} \end{gathered}[/tex]