The distance the penny will fall in the sixth seconds:
[tex]16,48,80,x,y,z[/tex][tex]\begin{gathered} T_1=16 \\ T_2=48 \\ T_3=80 \end{gathered}[/tex][tex]\begin{gathered} T_2-T_1=T_3-T_2 \\ 48-16=80-48=32 \end{gathered}[/tex][tex]\begin{gathered} x=80+32=112 \\ y=112+32=144 \\ z=144+32=176 \end{gathered}[/tex]
Therefore the distance the penny will fall in the sixth second = 176
