To answer this question, we need to apply the formula for the distance between two points:
[tex]d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Then, we have:
x1 = -6, y1 = 2
x2 = 6, y2 = -3
Thus, we have:
[tex]d=\sqrt[]{(6-(-6))^2+(-3-2)^2}\Rightarrow d=\sqrt[]{(6+6)^2+(-5)^2}\Rightarrow d=\sqrt[]{12^2+(-5)^2}[/tex]
Then, we have:
[tex]d=\sqrt[]{144+25}\Rightarrow d=\sqrt[]{169}\Rightarrow d=13[/tex]
Hence, the distance between these two points is d = 13 units.
