Given,
The refractive index of the medium, n₁=2
The angle of incidence, i=40°
The angle of refraction. r=10°
From Snell's law, we have,
[tex]\begin{gathered} n_1\sin i=n_2\sin r \\ \Rightarrow n_2=\frac{n_1\sin i}{\sin r} \end{gathered}[/tex]On substituting the known values,
[tex]\begin{gathered} n_2=\frac{2\times\sin40^{\circ}}{\sin10^{\circ}} \\ =7.4 \end{gathered}[/tex]Thus the refractive index obtained is 7.4
