[tex]\begin{gathered} \text{NOPQ was dilated to N'O'P'Q'} \\ \text{The scale factor is }\frac{2}{3} \\ N^{\prime}O^{\prime}=4 \\ N^{\prime}O^{\prime}=\frac{2}{3}NO \\ 4=\frac{2}{3}NO \\ \text{cross multiply} \\ 12=2NO \\ NO=\frac{12}{2} \\ NO=6 \end{gathered}[/tex]
