ANSWER :
2 and -4
EXPLANATION :
Let x = number
and
y = other number
Twice the number (2x)
minus another number (y) is 8
That will be :
2x - y = 8
Their sum is -2, so :
x + y = -2
We now have two equations and two unknowns.
[tex]\begin{gathered} 2x-y=8 \\ x+y=-2 \end{gathered}[/tex]Add the two equations to eliminate the variable y :
[tex]\begin{gathered} (2x+x)+(-y+y)=8+(-2) \\ 3x=6 \\ x=\frac{6}{3}=2 \end{gathered}[/tex]Substitute x = 2 to the second equation :
[tex]\begin{gathered} x+y=-2 \\ 2+y=-2 \\ y=-2-2 \\ y=-4 \end{gathered}[/tex]So the numbers are 2 and -4
