Solution:
Given the figure;
Triangle KOJ is similar to Triangle NOM.
The side-angle-side (SAS) theorem: If two sides and the included angle of one triangle are equal to two sides and the included angle of another triangle, the triangles are congruent.
Thus;
[tex]\begin{gathered} |KO|\cong|NO| \\ \\ |OJ|\operatorname{\cong}|OM| \\ \\ m\angle O\cong m\angle O \\ \\ \triangle KOJ\operatorname{\cong}\triangle NOM \end{gathered}[/tex]
