Hello
To solve this question, we simply need to use the formula of findind the pH of a solution.
[tex]\begin{gathered} pH=-\text{log}\lbrack H_2O^+\rbrack \\ pH=-\log \lbrack1.25\times10^{-1}\rbrack \\ pH=0.903\approx0.9 \end{gathered}[/tex]From the calculation above, the pH of the solution is 0.9 and this indicates that it is a strong acidic solution.
