We can solve this questions using the formula:
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]where P is the initial tuition fee, r is the rate at which it increases in decimal form, n is the number of times it increases per year and t is the number of years it increased.
Then:
[tex]A=4300(1+\frac{0.04}{1})^{1\cdot20}=9422[/tex]Therefore, the tuition will be $9422 in 2020.