We want to find a number x such that 10% more of that number is equal to 132.
1) We can write the 10% of the number x as:
[tex]\frac{10}{100}\cdot x=0.1x\text{.}[/tex]2) Now, 10% more of the number x is:
[tex]x+0.1x=1.1x\text{.}[/tex]So we have that:
[tex]1.1x=132.[/tex]3) To solve the last equation, we divide both sides by 1.1:
[tex]\begin{gathered} \frac{1.1x}{1.1}=\frac{132}{1.1}, \\ x=120. \end{gathered}[/tex]Answer
The number is 120.
