ANSWER
The pressure of the gas is 2.82 atm
EXPLANATION
Given that;
The moles of the gas is 0.30 moles
The volume of the gas is 2.53L
The temperature of the gas is 290K
Follow the steps below to find the pressure of the gas
Assume is the gas behaves like an ideal gas
[tex]\text{ PV = nRT}[/tex]Substitute the given data into the formula above
[tex]\begin{gathered} \text{ Recall, that the universal gas constant is 0.08205 L. atm . mol}^{-1}.\text{ K}^{-1} \\ \text{ P }\times\text{ 2.53 = 0.3 }\times\text{ 290}\times\text{ 0.08205} \\ \text{ 2.53P = 7.13835} \\ \text{ Divide both sides by 2.53} \\ \text{ P = }\frac{\text{ 7.13835}}{\text{ 2.53}} \\ \text{ P = 2.82 atm} \end{gathered}[/tex]Therefore, the pressure of the gas is 2.82 atm