Answer:
Choosing 1 basket at random, the probability that it contains candy and coffee is;
[tex]P(C\cap Co)=0.256[/tex]Explanation:
Given the table in the attached image.
Choosing 1 basket at random, the probability that it contains candy and coffee would be;
[tex]P(C\cap Co)=\frac{\text{ number of baskets with candy and coffee}}{\text{ total number of baskets}}[/tex]Given;
[tex]\begin{gathered} \text{number of baskets with candy and coffee = }11 \\ \text{total number of baskets = 43} \end{gathered}[/tex]substituting;
[tex]\begin{gathered} P(C\cap Co)=\frac{\text{ number of baskets with candy and coffee}}{\text{ total number of baskets}}=\frac{11}{43} \\ P(C\cap Co)=0.256 \end{gathered}[/tex]Therefore, Choosing 1 basket at random, the probability that it contains candy and coffee is;
[tex]P(C\cap Co)=0.256[/tex]