Given:
Cone with radius 8 feet, and height 12 feet
Recall that the formula for determining the volume of cone is
[tex]V=\frac{\pi r^2h}{3}[/tex]
Given the following dimensions, substitute r = 8 ft, and h = 12 ft.
[tex]\begin{gathered} V=\frac{\pi r^{2}h}{3} \\ V=\frac{\pi(8\text{ ft})^2(12\text{ ft})}{3} \\ V=\frac{(64\text{ ft}^2)(12\text{ ft})\pi}{3} \\ V=\frac{768\pi\text{ ft}^3}{3} \\ V=256\pi\text{ ft}^3 \\ \\ \text{Therefore, the volume of the cone is }256\pi\text{ ft}^3. \end{gathered}[/tex]
