Answer
[tex]3(x+4)(x-4)[/tex]
Explanation
Given:
[tex]3x^2-48[/tex]
48 is a multiple of 3:
[tex]\frac{48}{3}=16[/tex]
Thus, if we get 3 as a common factor of the expression we would get:
[tex]3(x^2-16)[/tex]
Then, the expression inside the parenthesis is a difference of squares. The difference of squares is factorized as follows:
[tex](x^2-a^2)=(x+a)(x-a)[/tex]
The square root of 16 is 4:
[tex]\sqrt{16}=4[/tex]
Thus, the expression given using the rule above would be:
[tex]3(x+4)(x-4)[/tex]
