We have to factorized this polynomial.
To do that we can look for common factors between the two terms.
We decomposed each term as:
[tex]\begin{gathered} 22m^6=2\cdot11\cdot m^6 \\ 12n^6=2\cdot2\cdot3\cdot m^6 \end{gathered}[/tex]
So only the factor 2 is common to both terms, so we can write the polynomial as:
[tex]22m^6-12n^6=2(11m^6-6n^6)[/tex]
Answer: 2*(11m^6-6n^6)
