Respuesta :

Given:

The solved quadratic equation is given.

Required:

To describe and correct each error.

Answer:

Let us find the the error.

[tex]\begin{gathered} 10\nu^2-46\nu=20 \\ 10\nu^2-46\nu-20=0 \\ 2(5\nu^2-23\nu-10)=0 \\ 5\nu^2-23\nu-10=0 \\ 5\nu^2-25\nu+2\nu-10=0 \\ 5\nu(\nu-5)+2(\nu-5)=0 \\ (\nu-5)(5\nu+2)=0 \\ (\nu-5)=0,(5\nu+2)=0 \\ \nu=5,5\nu=-2 \\ \nu=5,\nu=\frac{-2}{5} \end{gathered}[/tex]

Hence, the error is

[tex](\nu-25),(\nu+2)[/tex]

There should be

[tex](\nu-5),(5\nu+2)[/tex]

in the calculation.

Final Answer:

The error is

[tex](\nu-25),(\nu+2)[/tex]