The coordinates of D' = (-4,6)
The coordinates of E' = (4,2)
The coordinates of F' = (-2,-2)
Since triangle D'E'F' is the result of dilating triangle DEF with a scale factor of 2
then dilating triangle D'E'F' with a scale factor of 1 / 2 should give us triangle DEF.
Hence,
[tex]\begin{gathered} D=\frac{1}{2}(-4,6)=(-2,3) \\ E=\frac{1}{2}(4,2)=(2,1) \\ F=\frac{1}{2}(-2,-2)=(-1,-1) \end{gathered}[/tex]
