we know that
The student wrote the equation
[tex]f(x)=-4sin\frac{pi}{6}x+5[/tex]
For x=0, f(x)=1 -----> information given by the table
but
if you substitute x=0 in the equation
[tex]\begin{gathered} f(x)=-4s\imaginaryI n\frac{p\imaginaryI}{6}(0)+5 \\ f(x)=5 \end{gathered}[/tex]
The equation is not correct to model the data
therefore
The answer is option B
