Please help. A triangle has sides of length 7 in and 20 in with an included angle of 64

Given the following information
length1=7 in
length2=20 in
formed angle =64
the height h is given by
[tex]h=20sin(64)[/tex][tex]h=17.976[/tex]Area of the triangle is
[tex]A=\frac{b*h}{2}[/tex][tex]A=\frac{7*17.976}{2}[/tex][tex]A=62.916[/tex]units are
[tex]in^2[/tex]