a. Use the quadratic equation to find the zeros of the function. b. Average the zeros to find the x-coordinate of the vertex of the parabola.

y= x^2 - 13x + 36
Quadratic equation:
[tex]\frac{-b\pm\sqrt[]{b^2-4\cdot a\cdot c}}{2\cdot a}[/tex]Where:
a= 1
b= -13
c = 36
Replacing:
[tex]\frac{-(-13)\pm\sqrt[]{(-13)^2-4\cdot1\cdot36}}{2\cdot1}[/tex][tex]undefined[/tex]