Respuesta :

We have the next quadratic equation

[tex]3x^2-4x-5=0[/tex]

where

a=3

b=-4

c=-5

the quadratic formula is

[tex]x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]

we substitute the values

[tex]x_{1,2}=\frac{-(-4)\pm\sqrt[]{(-4)^2-4(3)(-5)}}{2(3)}[/tex]

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