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Question 30Jim has received scores of 70 and 72 on his first two 100 point tests.What score must he get on his third 100 point test to keep an average of 75.2 or greater?Third test >O No solution

Respuesta :

Answer:[tex]\text{Third score }\ge\text{ }83.6[/tex]Explanations:

First score = 70

Second score = 72

Third score = ?

[tex]\begin{gathered} \text{Average = }\frac{First\text{ score + Second score + Third score}}{3}\text{ } \\ \end{gathered}[/tex][tex]\begin{gathered} \text{Average = }\frac{70+72+(Third\text{ score)}}{3} \\ \text{Average = }\frac{142+(Third\text{ score)}}{3} \end{gathered}[/tex][tex]\text{Average }\ge\text{ 75.2}[/tex][tex]\begin{gathered} \frac{142+Third\text{ score}}{3}\ge75.2 \\ 142\text{ + Third score }\ge\text{ 3(75.2)} \\ 142\text{ + Third score }\ge\text{ }225.6 \\ \text{Third score }\ge\text{ 225.6 - 142} \\ \text{Third score }\ge\text{ }83.6 \end{gathered}[/tex]

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