Given the following inequality:
[tex]2\lbrack5x-(3x-4)\rbrack>2(2x+3)[/tex]
You can solve it as follows:
1. You need to distribute the negative sign on the left side of the inequality:
[tex]2\lbrack5x-3x+4\rbrack>2(2x+3)[/tex]
2. You can apply the Distributive Property on both sides of the inequality:
[tex]\begin{gathered} (2)(5x)+(2)(-3x)+(2)(4)>(2)(2x)+(2)(3) \\ 10x-6x+8>4x+6 \end{gathered}[/tex]
3. Now you can subtract this term from both sides of the inequality:
[tex]\begin{gathered} 10x-6x+8-(4x)>4x+6-(4x) \\ 10x-10x+8>6 \end{gathered}[/tex]
4. You can determine that:
[tex]8>6\text{ (True)}[/tex]
Therefore, you can conclude that all the values of "x" are solutions.
The answer is:
[tex](-\infty,\infty)[/tex]
