Given:
The total number of jeans is, j = 2.
The cost of jeans is, c (j) = $60.
The cos of t shirts is, c (t) = $12.
The total budjet of the purchase is, T = $130.
The objective is to find the maximum number of t-shirts that can be buy.
Explanaion:
Consider the number of t-shirts as t.
Then, the equation of cost can be written as,
[tex]\begin{gathered} j(c(j))+t(c(t))=T \\ 2($60$)+t(12)\le130\text{ . . . .(1)} \end{gathered}[/tex]To find t :
On solving the equation for t,
[tex]\begin{gathered} 120+12t=130 \\ 12t=130-120 \\ 12t=10 \\ t=\frac{10}{12} \\ t=0.83333\ldots. \end{gathered}[/tex]Since the value of t-shirt is less than 1, the person cannot buy any t-shirt.
Hence, the maximum number of t-shirts that can be buy with a budjet of $130 is zero.
